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Exact solution for buckling of axially-compressed cylindrical panels with frames attached to the circular edges

Abstract

This paper presents an exact solution for the boundary-value problem which describes the linear buckling of axially-compressed cylindrical panels with frames attached to the circular edges. The boundary conditions differ from the classical simply supported ones, often assumed for design purposes, in the sense that the torsion resisted by the frames are also taken into account. The quality of the results reported herein may be valuable benchmark data.

Keywords:
Cylindrical panel; Buckling; Exact solution; Frame

Graphical Abstract

1 INTRODUCTION

A reinforced circular cylindrical shell is sketched in Figure 1, with skin, stringers (longitudinal stiffeners) and frames (circumferential stiffeners) displayed. An isolated panel, extracted from a skin portion between adjacent stiffeners, is also indicated. In order to better exploit the structure load capacity, as done for instance in a typical aeronautical design, the skin is assumed to buckle first (Kollár and Dulácska, 1984Kollár, L., Dulácska, E. (1984). Buckling of Shells for Engineers, Wiley (Chichester).; Buermann et al., 2006Buermann, P., Rolfes, R., Tessmer, J., Schagerl, M. (2006). A semi-analytical model for local post-buckling analysis of stringer- and frame-stiffened cylindrical panels, Thin-Walled Structures 44(1):102-114.). In this case, the isolated panel can thus be used as a simple solution domain to estimate the skin buckling.

The exact solution for buckling of axially-compressed cylindrical panels with all edges simply supported in the classical manner is easy to be found (Timoshenko and Gere, 1961Timoshenko, S.P., Gere, J.M. (1961). Theory of Elastic Stability, 2nd edn., McGraw-Hill (New York).). Chu and Krishnamoorthy (1967Chu, K.H., Krishnamoorthy, G. (1967). Buckling of open cylindrical shells, Journal of the Engineering Mechanics Division, 93(EM 2):177-205.) reported an exact solution for the buckling of axially-compressed cylindrical panels with the circular edges simply supported and the straight edges free. By constraining the above free edges with stiffeners acting like beams, Krishnamoorthy (1974) proposed the first exact solution for panels with edge stiffeners.

More recently, axially compressed cylindrical panels with three edges simply supported and one edge free were treated by Magnucki and Maćkiewicz (2006Magnucki, K., Maćkiewicz, M. (2006). Elastic buckling of an axially compressed cylindrical panel with three edges simply supported and one edge free, Thin-Walled Structures 44(4):387-392.) and by Wilde et al. (2007Wilde, R., Zawodny, P., Magnucki, K. (2007). Critical state of an axially compressed cylindrical panel with three edges simply supported and one edge free, Thin-Walled Structures 45(10-11):955-959.) using, respectively, the Galerkin and Lévy-type procedures. Varying the load from pure compression to full in-plane bending, the buckling of simply supported cylindrical panels was numerically analyzed by Martins et al. (2013Martins, J.P., Simões da Silva, L., Reis, A. (2013). Eigenvalue analysis of cylindrically curved panels under compressive stresses - Extension of rules from EN 1993-1-5, Thin-Walled Structures 68:183-194.). Parametric results for the buckling of axially-compressed cylindrically panels with the circular edges simply supported and the straight edges free were provided by

Figure 1:
Cylindrical shell reinforced with stringers and frames.

Eipakchi and Shariati (2011Eipakchi, H.R., Shariati, M. (2011). Buckling analysis of a cylindrical panel under axial stress using perturbation technique, Journal of Applied Mathematics and Mechanics 91(2):138-145.), and by Afkhami et al. (2015Afkhami, S.E., Vahid, M., Niazi, M., Abbasi, M. (2015). Analytical and numerical investigations on buckling of an axially compressed cylindrical panel with specific boundary condition, International Review of Mechanical Engineering 9(2):118-123.) using, respectively, a perturbation technique and the Galerkin method.

Focusing on bridge construction aspects, Tran et al. (2012Tran, K.L, Davaine, L., Douthe, C., Sab, K. (2012). Stability of curved panels under uniform axial compression, Journal of Constructional Steel Research 69:30-38.) studied the linear buckling and the ultimate strength of stiffened cylindrical panels under axial compression. Finally, the state-of-the-art on the stability behavior and design of cylindrical panels under generalized in-plane loading is well detailed in Martins et al. (2018Martins, J.P., Ljubinkovic, F., Simões da Silva, L., Gervásio, H. (2018). Behaviour of thin-walled curved steel plates under generalised in-plane stresses: a review, Journal of Constructional Steel Research 140:191-207.). None of the previous works have treated the problem addressed here.

Axially-loaded stiffened cylindrical shells are generally low sensitive, or even insensitive, to imperfections depending on how closely stiffened they are (Koiter, 1956Koiter, W.T. (1956). Buckling and post-buckling behaviour of a cylindrical panel under axial compression, Rep. No. NLL-TR S. 476, National Aerospace Research Institute (Amsterdam).; Stephens, 1971Stephens, W.B. (1971). Imperfection sensitivity of axially compressed stringer reinforced cylindrical panels under internal pressure, AIAA J. 9(9):1713-1719.; Singer, 2004Singer, J. (2004). Stiffened cylindrical shells, In: Teng, J.G., Rotter, J.M., eds., Buckling of Thin Metal Shells, Spon Press (London), 286-343.). Due to the difficult of determining the actual imperfection, their design at present is still based on classical critical loads corrected by knockdown factors. In particular, with regard to the aerospace structures, prediction of knockdown factors remains highly dependent on the empirical guideline provided in NASA SP-8007 (Peterson et al., 1968Peterson, J.P., Seide, P., Weingarten, V.I. (1968). Buckling of thin-walled circular cylinders, Report NASA-SP-8007, National Aeronautics and Space Administration (Hampton).). Moreover, the linearized buckling analysis can still be used to predict lower bounds on the critical load, as proposed by Sosa et al. (2006Sosa, E.M., Godoy, L.A., Croll, J.G.A. (2006). Computation of lower-bound elastic buckling loads using general-purpose finite element codes, Computers and Structures 84(29-30):1934-1945.).

Following closely the work of Lucena Neto et al. (2016Lucena Neto, E., Monteiro, F.A.C., Soares, P.T.M.L. (2016). Exact solution for buckling of axially compressed cylindrical panels with stringers attached to the straight edges, Journal of Engineering Mechanics 142(16):04016028.), one develops herein a procedure that exactly predict the linear buckling load for axially-compressed cylindrical panels with frames attached to the circular edges, identifying the external moments exerted by them on the buckling onset. From a mathematical point of view, the simple change of the stiffener from the straight edges (see Lucena Neto et al., 2016) to the circular ones in the panel is enough to make the problem challenging in stating the moments exerted by the frames on the circular edges and in establishing all the function spaces where a buckling mode might be. In the proposed solution, the frames are supposed to resist torsion in three ways: the first and second are denoted by Saint-Venant and warping torsions (Kollbrunner and Basler, 1969Kollbrunner, C.F., Basler, K. (1969). Torsion in Structures, Springer (Berlin).; Pilkey, 2002Pilkey, W.D. (2002). Analysis and Design of Elastic Beams: Computational Methods, John Wiley (New York).), respectively, while the third is associated with the frame out-of-plane bending.

The linearized Donnell's equations, with prebuckling rotations neglected, are chosen to describe the panel buckling behavior (Brush and Almroth, 1975Brush, D.O., Almroth, B.O. (1975). Buckling of Bars, Plates, and Shells, McGraw-Hill (New York).). The exact solution is stated here in a suitable detail, which may be valuable benchmark data.

2 PROBLEM FORMULATION

The circular cylindrical panel shown in Figure 2(a) has radius R, length a, width b and thickness h. It is subjected to a uniformly distributed axial compressive force p per unit length and referred to a set of orthogonal curvilinear coordinates xyz placed in the panel midsurface. The panel buckling is supposed to be described by the linearized Donnell's equations (Brush and Almroth, 1975Brush, D.O., Almroth, B.O. (1975). Buckling of Bars, Plates, and Shells, McGraw-Hill (New York).; Lucena Neto et al., 2016Lucena Neto, E., Monteiro, F.A.C., Soares, P.T.M.L. (2016). Exact solution for buckling of axially compressed cylindrical panels with stringers attached to the straight edges, Journal of Engineering Mechanics 142(16):04016028.)

4 u = - ν w , ξ ξ ξ + w , ξ η η 4 v = - 2 + ν w , ξ ξ η - w , η η η 8 w + w , ξ ξ ξ ξ + 2 ρ 4 w , ξ ξ = 0 (1)

with prebuckling rotations neglected. The nondimensional coordinates and displacements are defined as

Figure 2:
Cylindrical panel with frames attached to the circular edges: (a) geometry and loading; (b) boundary conditions.

ξ = 2 E h p c l x R η = 2 E h p c l y R u ξ , η = 2 E h p c l u x , y R v ξ , η = 2 E h p c l v x , y R w ξ , η = w x , y R (2)

where

p c l = E h 2 R 3 1 - ν 2 ρ = p p c l . (3)

The classical value pcl represents the minimum buckling load p that a simply supported panel could ever achieve. Moreover, u, v and w are the midsurface displacements in the x, y and z directions; E is the Young's modulus, ν is the Poisson's ratio, 8 denotes two successive applications of the two-dimensional biharmonic operator 4=,ξξξξ+2,ξξηη+,ηηηη and a comma followed by ξ (or η) indicates differentiation with respect to ξ (or η).

The boundary conditions (see Figure 2(b)) to be applied differ from the classical simply supported ones in the sense that the torsion resisted by the frames attached to the panel circular edges are also taken into account:

N ξ = 0 v = 0 w = 0 M ξ = M - a t ξ = ± ξ 0 u = 0 N η = 0 w = 0 M η = 0 a t η = 0 , η 0 (4)

with

ξ 0 = 2 E h p c l a 2 R η 0 = 2 E h p c l b R . (5)

The nondimensional in-plane forces Nξ and Nη, bending moments Mξ and Mη and external moments M- exerted by the frames on the panel circular edges ξ=± ξ0 are

N ξ = E h 1 - ν 2 u , ξ + ν v , η + ν w N η = E h 1 - ν 2 ν u , ξ + v , η + w M ξ = - D R 2 E h p c l w , ξ ξ + ν w , η η M η = - D R 2 E h p c l ν w , ξ ξ + w , η η M - ± ξ 0 , η = E f I f R 2 2 E h p c l u , η η ± ξ 0 , η - w , ξ ± ξ 0 , η G f J f R 2 2 E h p c l u , η η ± ξ 0 , η + 2 E h p c l w , ξ η η ± ξ 0 , η ± E f Γ f R 4 2 E h p c l 3 / 2 u , η η η η ± ξ 0 , η + 2 E h p c l w , ξ η η η η ± ξ 0 , η (6)

where D=Eh3/121-ν2 is the panel bending rigidity.

Note that the external moment, which prevent the panel circular edges from rotating freely, is prescribed but not known until the problem is completed solved. Details on its expression development is given in Appendix A. The frames have torsional and warping constants Jf and Γf, area moment of inertia of the cross section about the z axis given by If, material with Young's modulus Ef and shear modulus Gf. The first term in M- is associated with the frame out-of-plane bending, while the second and third terms are associated with Saint-Venant and warping torsions, respectively.

3 CHARACTERISTIC EQUATION AND SOLUTION PROCEDURE

A general buckling mode satisfying the simply supported boundary conditions on edges η=0, η0, can be assumed in the form

u ξ , η = U ξ sin k η v ξ , η = V ξ cos k η w ξ , η = W ( ξ ) sin k η , (7)

with

k = n π R b p c l 2 E h (8)

and the integer n standing for the number of half-waves in the circumferential direction. The functions U(ξ), V(ξ) and W(ξ) must be obtained so that the mode fulfills the conditions required by the supports at ξ=±ξ0 and satisfies (1).

After substitution of (7), the boundary conditions (4) on edges ξ=±ξ0 hold for every 0<η<η0 if

U , ξ ± ξ 0 = 0 V ± ξ 0 = 0 W ( ± ξ 0 ) = 0 D R W , ξ ξ ( ± ξ 0 ) ± p c l 2 E h E f I f R 2 + n 2 π 2 b 2 G f J f + n 4 π 4 b 4 E f Γ f W , ξ ( ± ξ 0 ) ± n 2 π 2 b 2 p c l 2 E h 3 2 E f I f + G f J f + n 2 π 2 b 2 E f Γ f U ± ξ 0 = 0 . (9)

On the other hand, the equation obtained after substitution of wξ,η into the third of equations (1) holds for every point ξ,η of the domain for nontrivial w (i.e., W0) if

d 8 W d ξ 8 - 2 2 k 2 - ρ d 6 W d ξ 6 + 6 k 4 - 4 ρ k 2 + 1 d 4 W d ξ 4 - 2 k 4 2 k 2 - ρ d 2 W d ξ 2 + k 8 W = 0 . (10)

Particular solutions of this homogeneous linear differential equation are in the form esξ, where s denotes a root of the characteristic equation

s 8 - 2 2 k 2 - ρ s 6 + 6 k 4 - 4 ρ k 2 + 1 s 4 - 2 k 4 2 k 2 - ρ s 2 + k 8 = 0 . (11)

Closed-form solutions of polynomial equations beyond sixth order are restricted, except in the numerical form (King, 1996King, B.R. (1996). Beyond the Quartic Equation, Birkhäuser (Boston).;. McNamee, 2007McNamee, J.M. (2007). Numerical Methods for Roots of Polynomials, Part I, Elsevier (Amsterdam).; McNamee and Pan, 2013). Fortunately, equation (11) can be factored in the form

s 2 - k 2 s 4 + 2 ρ s 2 - k 2 s 2 + 1 = 0 (12)

regardless of the values of k and ρ. Thus, its roots are

s = ± i λ i ± 4 k 2 - λ i 2 (13)

where

λ 1 = ρ - ρ 2 - 1 λ 2 = ρ + ρ 2 - 1 (14)

and i=-1 denotes the imaginary unit. It is clear from physical considerations that the buckling will always take place for ρ>1 due to the attachment of frames to the panel edges ξ=±ξ0. In view of this evidence, the parameters λ2>λ1>0.

The presence of the constant term k8 (k>0) in (11) and the property λi>0 anticipate that zero and real roots do not exist. Depending on the values of λi and k, the roots may be grouped according to the five cases in the sequel.

3.1 Case I: 0<k2<λ1/4

All the roots are distinct and purely imaginary:

s 1 = - s 5 = i γ 1 s 2 = - s 6 = i γ 2 s 3 = - s 7 = i γ 3 s 4 = - s 8 = i γ 4 (15)

with

γ 1 γ 2 = λ 1 ± λ 1 - 4 k 2 2 γ 3 γ 4 = λ 2 ± λ 2 - 4 k 2 2 . (16)

The solution of (10) may then be taken in the form

W ( ξ ) = W 1 sin γ 1 ξ + W 2 cos γ 1 ξ + W 3 sin γ 2 ξ + W 4 cos γ 2 ξ + W 5 sin γ 3 ξ + W 6 cos γ 3 ξ + W 7 sin γ 4 ξ + W 8 cos γ 4 ξ (17)

where Wi are arbitrary constants.

Because the yz plane is a symmetry plane for the structure (see Figure 2(a)), the buckling modes can be separated into two distinct symmetry classes, which may be readily identified by the shape of W(ξ). The modes may be classified by whether the displacement component w is symmetric or antisymmetric with respect to the yz plane. The displacement components u and v will then also have appropriate symmetries. This separation not only aids in identifying and classifying the buckling mode, but also reduces the eigenvalue problem to two distinct problems with smaller determinants to be evaluated. Using the subscripts “s” and “a” to refer to symmetric and antisymmetric parts, Eq. (17) is split into

W s ( ξ ) = W 1 s cos γ 1 ξ + W 2 s cos γ 2 ξ + W 3 s cos γ 3 ξ + W 4 s cos γ 4 ξ W a ξ = W 1 a sin γ 1 ξ + W 2 a sin γ 2 ξ + W 3 a sin γ 3 ξ + W 4 a sin γ 4 ξ (18)

where Wis and Wia are appropriate redefinitions of Wi. From (1), (7) and (18), the functions U(ξ) and V(ξ) may also be split into

U s ξ = W 1 s u 1 s sin γ 1 ξ + W 2 s u 2 s sin γ 2 ξ + W 3 s u 3 s sin γ 3 ξ + W 4 s u 4 s sin γ 4 ξ U a ξ = W 1 a u 1 a cos γ 1 ξ + W 2 a u 2 a cos γ 2 ξ + W 3 a u 3 a cos γ 3 ξ + W 4 a u 4 a cos γ 4 ξ V s ξ = W 1 s v 1 s cos γ 1 ξ + W 2 s v 2 s cos γ 2 ξ + W 3 s v 3 s cos γ 3 ξ + W 4 s v 4 s cos γ 4 ξ V a ξ = W 1 a v 1 a sin γ 1 ξ + W 2 a v 2 a sin γ 2 ξ + W 3 a v 3 a sin γ 3 ξ + W 4 a v 4 a sin γ 4 ξ . (19)

The coefficients uis, uia, vis and via are detailed in Appendix B.

Introduction of the symmetric (or antisymmetric) displacement components (18) and (19) into (9) for ξ=ξ0 yields the homogeneous system of equations

K W = 0 , (20)

where the vector W collects Wis (or Wia) and the matrix K is given in Appendix B. Each root ρ of the equation detK=0 represents a buckling load.

Since similar expressions to (20) hold for the remaining cases, for which the matrix K is also listed in Appendix B, only the functions U(ξ), V(ξ) and W(ξ) associated with the solution will be summarized next.

3.2 Case II: k2=λ1/4

As the parameters γ1=γ2 in (16), the roots (15) reduces to

s 1 = s 2 = - s 5 = - s 6 = i γ 1 s 3 = - s 7 = i γ 3 s 4 = - s 8 = i γ 4 . (21)

The solutions (18) and (19) must be modified to account for the repeated roots s1=s2 and s5=s6:

W s ( ξ ) = W 1 s cos γ 1 ξ + W 2 s ξ sin γ 1 ξ + W 3 s cos γ 3 ξ + W 4 s cos γ 4 ξ W a ξ = W 1 a sin γ 1 ξ + W 2 a ξ cos γ 1 ξ + W 3 a sin γ 3 ξ + W 4 a sin γ 4 ξ U s ξ = W 1 s u 1 s + W 2 s u 2 s sin γ 1 ξ + W 2 s u - 2 s ξ cos γ 1 ξ + W 3 s u 3 s sin γ 3 ξ + W 4 s u 4 s sin γ 4 ξ U a ξ = W 1 a u 1 a + W 2 a u 2 a cos γ 1 ξ + W 2 a u - 2 a ξ sin γ 1 ξ + W 3 a u 3 a cos γ 3 ξ + W 4 a u 4 a cos γ 4 ξ V s ξ = ( W 1 s v 1 s + W 2 s v 2 s ) cos γ 1 ξ + W 2 s v - 2 s ξ sin γ 1 ξ + W 3 s v 3 s cos γ 3 ξ + W 4 s v 4 s cos γ 4 ξ V a ξ = W 1 a v 1 a + W 2 a v 2 a sin γ 1 ξ + W 2 a v - 2 a ξ cos γ 1 ξ + W 3 a v 3 a sin γ 3 ξ + W 4 a v 4 a sin γ 4 ξ . (22)

The coefficients uis, u-is, uia, u-ia, vis, v-is, via, v-ia are detailed in Appendix B.

3.3 Case III: λ1/4<k2<λ2/4

All the roots are distinct. Roots s1, s2, s5, s6 are the complex roots

s 1 = - s 5 s 2 = - s 6 = α 1 ± i β 1 (23)

with

α 1 = 4 k 2 - λ 1 2 β 1 = λ 1 2 , (24)

and roots s3, s4, s7, s8 are the purely imaginary roots identified in Case I. Splitting the solution of (10) into symmetric and antisymmetric parts as before,

W s ( ξ ) = W 1 s sinh α 1 ξ sin β 1 ξ + W 2 s cosh α 1 ξ cos β 1 ξ + W 3 s cos γ 3 ξ + W 4 s cos γ 4 ξ W a ( ξ ) = W 1 a sinh α 1 ξ cos β 1 ξ + W 2 a cosh α 1 ξ sin β 1 ξ + W 3 a sin γ 3 ξ + W 4 a sin γ 4 ξ U s ξ = W 1 s u 1 s + W 2 s u 2 s sinh α 1 ξ cos β 1 ξ + W 1 s u - 1 s + W 2 s u - 2 s cosh α 1 ξ sin β 1 ξ + W 3 s u 3 s sin γ 3 ξ + W 4 s u 4 s sin γ 4 ξ U a ξ = W 1 a u 1 a + W 2 a u 2 a sinh α 1 ξ sin β 1 ξ + W 1 a u - 1 a + W 2 a u - 2 a cosh α 1 ξ cos β 1 ξ + W 3 a u 3 a cos γ 3 ξ + W 4 a u 4 a cos γ 4 ξ V s ξ = W 1 s v 1 s + W 2 s v 2 s sinh α 1 ξ sin β 1 ξ + W 1 s v - 1 s + W 2 s v - 2 s cosh α 1 ξ cos β 1 ξ + W 3 s v 3 s cos γ 3 ξ + W 4 s v 4 s cos γ 4 ξ V a ξ = W 1 a v 1 a + W 2 a v 2 a sinh α 1 ξ cos β 1 ξ + W 1 a v - 1 a + W 2 a v - 2 a cosh α 1 ξ sin β 1 ξ + W 3 a v 3 a sin γ 3 ξ + W 4 a v 4 a sin γ 4 ξ . (25)

The coefficients uis, u-is, uia, u-ia, vis, v-is, via, v-ia are detailed in Appendix B.

3.4 Case IV: k2=λ2/4

Roots s1, s2, s5, s6 are the complex roots identified in Case III, whereas s3, s4, s7, s8 reduce to the purely imaginary roots

s 3 = s 4 = - s 7 = - s 8 = i γ 3 . (26)

In order to account for the repeated roots s3=s4 and s7=s8, the solution (25) must be modified to read

W s ξ = W 1 s sinh α 1 ξ sin β 1 ξ + W 2 s cosh α 1 ξ cos β 1 ξ + W 3 s cos γ 3 ξ + W 4 s ξ sin γ 3 ξ W a ξ = W 1 a sinh α 1 ξ cos β 1 ξ + W 2 a cosh α 1 ξ sin β 1 ξ + W 3 a sin γ 3 ξ + W 4 a ξ cos γ 3 ξ U s ξ = W 1 s u 1 s + W 2 s u 2 s sinh α 1 ξ cos β 1 ξ + W 1 s u - 1 s + W 2 s u - 2 s cosh α 1 ξ sin β 1 ξ + W 3 s u 3 s + W 4 s u 4 s sin γ 3 ξ + W 4 s u - 4 s ξ cos γ 3 ξ U a ξ = W 1 a u 1 a + W 2 a u 2 a sinh α 1 ξ sin β 1 ξ + W 1 a u - 1 a + W 2 a u - 2 a cosh α 1 ξ cos β 1 ξ + W 3 a u 3 a + W 4 a u 4 a cos γ 3 ξ + W 4 a u - 4 a ξ sin γ 3 ξ V s ξ = W 1 s v 1 s + W 2 s v 2 s sinh α 1 ξ sin β 1 ξ + W 1 s v - 1 s + W 2 s v - 2 s cosh α 1 ξ cos β 1 ξ + W 3 s v 3 s + W 4 s v 4 s cos γ 3 ξ + W 4 s v - 4 s ξ sin γ 3 ξ V a ξ = W 1 a v 1 a + W 2 a v 2 a sinh α 1 ξ cos β 1 ξ + W 1 a v - 1 a + W 2 a v - 2 a cosh α 1 ξ sin β 1 ξ + W 3 a v 3 a + W 4 a v 4 a sin γ 3 ξ + W 4 a v - 4 a ξ cos γ 3 ξ . (27)

The coefficients uis, u-is, uia, u-ia, vis, v-is, via, v-ia are detailed in Appendix B.

3.5 Case V: λ2/4<k2

All the roots are distinct and complex:

s 1 = - s 5 s 2 = - s 6 = α 1 ± i β 1 s 3 = - s 7 s 4 = - s 8 = α 2 ± i β 2 (28)

with

α i = 4 k 2 - λ i 2 β i = λ i 2 . (29)

The symmetric and antisymmetric solutions of (10) are

W s ξ = W 1 s sinh α 1 ξ sin β 1 ξ + W 2 s cosh α 1 ξ cos β 1 ξ + W 3 s sinh α 2 ξ sin β 2 ξ + W 4 s cosh α 2 ξ cos β 2 ξ W a ξ = W 1 a sinh α 1 ξ cos β 1 ξ + W 2 a cosh α 1 ξ sin β 1 ξ + W 3 a sinh α 2 ξ cos β 2 ξ + W 4 a cosh α 2 ξ sin β 2 ξ U s ξ = W 1 s u 1 s + W 2 s u 2 s sinh α 1 ξ cos β 1 ξ + W 1 s u - 1 s + W 2 s u - 2 s cosh α 1 ξ sin β 1 ξ + W 3 s u 3 s + W 4 s u 4 s sinh α 2 ξ cos β 2 ξ + W 3 s u - 3 s + W 4 s u - 4 s cosh α 2 ξ sin β 2 ξ U a ξ = W 1 a u 1 a + W 2 a u 2 a sinh α 1 ξ sin β 1 ξ + W 1 a u - 1 a + W 2 a u - 2 a cosh α 1 ξ cos β 1 ξ + W 3 a u 3 a + W 4 a u 4 a sinh α 2 ξ sin β 2 ξ + W 3 a u - 3 a + W 4 a u - 4 a cosh α 2 ξ cos β 2 ξ V s ξ = W 1 s v 1 s + W 2 s v 2 s sinh α 1 ξ sin β 1 ξ + W 1 s v - 1 s + W 2 s v - 2 s cosh α 1 ξ cos β 1 ξ + W 3 s v 3 s + W 4 s v 4 s sinh α 2 ξ sin β 2 ξ + W 3 s v - 3 s + W 4 s v - 4 s cosh α 2 ξ cos β 2 ξ V a ξ = W 1 a v 1 a + W 2 a v 2 a sinh α 1 ξ cos β 1 ξ + W 1 a v - 1 a + W 2 a v - 2 a cosh α 1 ξ sin β 1 ξ + W 3 a v 3 a + W 4 a v 4 a sinh α 2 ξ cos β 2 ξ + W 3 a v - 3 a + W 4 a v - 4 a cosh α 2 ξ sin β 2 ξ . (30)

The coefficients uis, u-is, uia, u-ia, vis, v-is, via, v-ia are detailed in Appendix B.

4 RESULTS

The nonlinear eigenvalue problem (20) cannot be written in a form to allow the direct use of some standard software package to solve it. The following iteration steps are then employed to identify the smallest root ρ of detK=0 for a given n associated with a symmetric or antisymmetric mode:

  1. evaluate k from (8);

  2. if k2<1/4 then Case I, II or III applies.

    • Case I: The root lies in Case I if ρI1=(1,α), with α=(16k4+1)/8k2. Search if the sign of detK changes in the interval I1. The search is made dividing the open interval in 104 equal subintervals, evaluating detK progressively from ρ=1+ε to α-ε, with ε=10-6. If the sign of the determinant changes, there is a root in that subinterval. Go to step 5. Otherwise, go to Case II.

    • Case II: If detK=0 with ρ=α save the root and stop the search for the given n. Otherwise, go to Case III. It has been accepted as null the value detK<10-9detK<10-9.

    • Case III: The root lies in Case III if ρ>α. Search if the sign of detK changes in the open interval I2=(α,2α) similarly to Case I. If the sign changes, there is a root in that subinterval. Go to step 5. Otherwise, stop the search for the given n;

  3. if k2=1/4 then only Case III applies. Do Case III;

  4. if k2>1/4 then Case V, IV or III applies.

    • Case V: The root lies in Case V if ρI1. Search if the sign of detK changes similarly to Case I. If the sign changes, there is a root in that subinterval. Go to step 5. Otherwise, go to Case IV.

    • Case IV: If detK=0 with ρ=α save the root and stop the search for the given n. Otherwise, go to Case III.

    • Case III: do Case III;

  5. search for the root in the subinterval where detK changes sign using some iterative methods. Herein one has employed the fzero function of MATLAB (2016) that finds roots of nonlinear functions using a combination of bisection, secant, and inverse quadratic interpolation methods. Save the root.

The critical value of ρ corresponds to the smallest value obtained for n=1, 2, 3, and for symmetric or antisymmetric modes. It is expected that the Cases II and IV will be rarely activated.

Table 1
Effect of the ratios b/a and R/h, and frame support on the buckling load ρ.

All the analyzed panels have length a=500 mm, thickness h=1 mm, and material defined by E=72400 N/mm2, ν=0.33. Several values are attributed to the width b and radius R. The frame has Jf=96 mm4, Γf=36370 mm6 and If=853 mm4 and material given by Ef=71020 N/mm2 and Gf=26700 N/mm2.

Table 1 summarizes the effect of the aspect ratio b/a and radius-to-thickness ratio R/h on the critical value of ρ. The half-wave number (n), mode type (symmetric, antisymmetric), and solution case (I, II, III, IV, V) are indicated in parentheses. The triple (Jf=0, Γf=0, If=0) identifies panels under the classical simply supported boundary conditions. The half-wave number for panels with frames never decreases as b/a increases (wide panels).

Figure 3 depicts the buckling modes for the following panels with frames: R/h=1000 and b/a=0.4, 0.6 and 1.4, including the moments exerted by the frame on the circular edge ξ=ξ0. As expected, the warping torsion contribution becomes more significant for buckling modes with higher circumferential half-wave numbers. It is interesting to note that, depending on the membrane effect, the out-of-plane bending torsion may have opposite sign compared to that of the Saint-Venant and warping torsions.

The load parameter pa2/π2D is plotted in Figure 4 against the curvature parameter Z=1-ν2 a2/Rh on a log-log scale for panels with and without frames, and aspect ratios b/a=0.5, 1 and 2. The curves are obtained varying R while all the remaining parameters are kept constant. The curves show that the influence of the frames is highly dependent on the curvature parameter. For instance, the frames may increase the buckling load as high as 37% for Z=2.85 and b/a = 1 and decrease it as Z increases. After Z100, the curves become nearly indistinguishable. The four marked points on each curve of Figure 4 represents the values of the critical load obtained from a Ritz procedure based on a complete hierarchic set of polynomial functions (Bardell, 1991Bardell, N.S. (1991). Free vibration analysis of a flat plate using the hierarchical finite element method, Journal of Sound Vibration 151 (2): 263-289.; Yshii et al., 2018Yshii, L.N., Lucena Neto, N., Monteiro, F.A.C., Santana, R.C. (2018). Accuracy of the buckling predictions of anisotropic plates, Journal of Engineering Mechanics 144(8):04018061.). The Ritz solutions are included here as a simple way of illustrating how the proposed results may be useful as benchmarks. The maximum difference between the exact and Ritz results is lower than 0.05%, observed for the panel with frames and b/a=0.5 and Z=100.

Figure 3:
Buckling modes and external moments M- exerted by the frame on the edges ξ=ξ0 for panels with R/h=1000: (a) b/a=0.4; (b) b/a=0.6; (c) b/a=1.4.

5 CONCLUSION

A Lévy-type procedure is adopted to develop, in a suitable detail, an exact solution for buckling of axially-compressed cylindrical panels with frames attached to the circular edges. The linearized Donnell’s equations, with prebuckling rotations neglected, are chosen to describe the buckling behavior. Both Saint-Venant and warping torsions, as well as the frame out-of-plane bending, are taken into account in the torsion resisted by the frames. The eight order characteristic equation is solved in closed form. An algorithm to generate numerical results is provided. Sets of exact results for specific panels and frames are tabled with which those from approximated procedures may be directly compared. While attached stringers on the straight edges may rise the buckling load to around 51% with respect to simply supported boundary conditions, as reported by Lucena Neto et al. (2016Lucena Neto, E., Monteiro, F.A.C., Soares, P.T.M.L. (2016). Exact solution for buckling of axially compressed cylindrical panels with stringers attached to the straight edges, Journal of Engineering Mechanics 142(16):04016028.), the attachment of frames on the circular edges may rise the buckling load as high as 37% considering the set of analyzed panels.

Figure 4:
Evolution of pa2/π2D with respect to Z=1-ν2a2/Rh for panels with: (a) b/a=0.5; (b) b/a=1; (c) b/a=2.

References

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APPENDIX A. EXPRESSION OF THE EXTERNAL MOMENT M-

Figure 5 shows an infinitesimal portion of the frame attached to the panel edge x=-a/2, under the action of the external moment M--a/2,y exerted by the panel and the internal force and moments due to the torsion of the frame. One finds on summing forces in the out-of-plane direction

- Q + Q + d Q = 0 d Q = 0 Q , y = 0 . (A.1)

The sum of moments about a vertical axis gives

- M t sin d θ 2 - M t + d M t sin d θ 2 - M cos d θ 2 + M + d M cos d θ 2 - Q d y = 0 (A.2)

or

M , y - M t R - Q = 0 (A.3)

by using cosdθ/21 and sindθ/2dθ/2 and neglecting higher order terms. Similarly, summing moments about a horizontal axis yields

M R + M t , y + M - = 0 . (A.4)

Note that the torsion and out-of-plane bending are coupled in the equilibrium equations (A.1), (A.3) and (A.4).

Based on the fundamental lemma of variational calculus (Gelfand and Fomin, 2000), the principle of virtual displacement associated with this problem must have the form

0 b Q , y δ u + M , y - M t R - Q δ θ z + M R + M t , y + M - δ θ y d y + = 0 . (A.5)

The boundary terms are not shown, θy and θz are the rotations about the y and z axes, and the coefficients of δu, δθz and δθy are the equilibrium equations (A.1), (A.3) and (A.4), respectively. It is convenient to write (Pilkey, 2002)

M t = M s v - M ω , y (A.6)

in which Msv and -Mω,y are the Saint-Venant and warping torsions (Mω denotes the bimoment). Thus,

0 b Q , y δ u + M , y - M s v R + M ω , y R - Q δ θ z + M R + M s v , y - M ω , y y + M - δ θ y d y + = 0 (A.7)

or, using integration by parts,

- 0 b M δ - θ y R + θ z , y + Q δ u , y + θ z + M s v δ θ y , y + θ z R + M ω δ θ y , y y + θ z , y R - M - δ θ y d y + = 0 . (A.8)

One can identify

- 0 b M δ - θ y R + θ z , y + Q δ u , y + θ z + M s v δ θ y , y + θ z R + M ω δ θ y , y y + θ z , y R d y (A.9)

as the internal virtual work, which suggests that

- θ y R + θ z , y u , y + θ z θ y , y + θ z R θ y , y y + θ z , y R (A.10)

are the work-conjugate strains to M, Q, Msv and Mω, respectively.

The second strain in (A.9) can be eliminated by the Euler-Bernoulli assumption θz=-u,y. The constitutive equations are then given by

M = - E f I f u , y y + θ y R M s v = G f J f θ y , y - u , y R M ω = E f Γ f θ y , y y - u , y y R . (A.11)

Substitution of (A.6) and (A.11) into (A.4), replacing the frame twist θy by -w,x, gives finally

M - = E f I f R u , y y - w , x R + G f J f u , y y R + w , x y y - E f Γ f u , y y y y R + w , x y y y y . (A.12)

A similar expression can be found in (Kang et al., 1996) in the context of vibrations of curved beams. The sense of M- shown in Figure 5 must be reversed for the frame attached to the panel edge x=a/2.

Figure 5:
Infinitesimal portion of the frame attached to the panel edge x=-a/2.

APPENDIX B. DISPLACEMENT COEFFICIENTS AND MATRIX K

The coefficients uis, u-is, uia, u-ia, vis, v-is, via, v-ia and entries of matrix K are listed in the sequel.

B.1 Case I

Symmetric modes:

u i s = γ i k 2 - ν γ i 2 k 2 + γ i 2 2 v i s = k k 2 + 2 + ν γ i 2 k 2 + γ i 2 2 i = 1 , 2 , 3 , 4 (B.1)

k 1 i = u i s γ i cos γ i ξ 0 k 2 i = v i s cos γ i ξ 0 k 3 i = cos γ i ξ 0 k 4 i = - D R γ i 2 cos γ i ξ 0 - A γ i sin γ i ξ 0 + B u i s sin γ i ξ 0 i = 1 , 2 , 3 , 4 (B.2)

in which

A = p c l 2 E h E f I f R 2 + n 2 π 2 b 2 G f J f + n 4 π 4 b 4 E f Γ f B = n 2 π 2 b 2 p c l 2 E h 3 / 2 E f I f + G f J f + n 2 π 2 b 2 E f Γ f . (B.3)

Antisymmetric modes:

u i a , v i a = - u i s , v i s i = 1 , 2 , 3 , 4 (B.4)

k 1 i = - u i a γ i sin γ i ξ 0 k 2 i = v i a sin γ i ξ 0 k 3 i = sin γ i ξ 0 k 4 i = - D R γ i 2 sin γ i ξ 0 + A γ i cos γ i ξ 0 + B u i a cos γ i ξ 0 i = 1 , 2 , 3 , 4 . (B.5)

B.2 Case II

Symmetric modes:

u 1 s , u 3 s , u 4 s , v 1 s , v 3 s , v 4 s = u 1 s , u 3 s , u 4 s , v 1 s , v 3 s , v 4 s o f C a s e I u 2 s = 1 + ν 4 k 2 v 2 s = 1 2 k 2 u - 2 s , v - 2 s = - u 1 s , v 1 s (B.6)

k 1 i = u i s γ i cos γ i ξ 0 k 12 = u 2 s γ 1 cos γ 1 ξ 0 + u - 2 s ( cos γ 1 ξ 0 - γ 1 ξ 0 sin γ 1 ξ 0 ) k 2 i = v i s cos γ i ξ 0 k 22 = v 2 s cos γ 1 ξ 0 + v - 2 s ξ 0 sin γ 1 ξ 0 k 3 i = cos γ i ξ 0 k 32 = ξ 0 sin γ 1 ξ 0 k 4 i = - D R γ i 2 cos γ i ξ 0 - A γ i sin γ i ξ 0 + B u i s sin γ i ξ 0 k 42 = D R γ 1 2 cos γ 1 ξ 0 - γ 1 ξ 0 sin γ 1 ξ 0 + A sin γ 1 ξ 0 + γ 1 ξ 0 cos γ 1 ξ 0 + B u 2 s sin γ 1 ξ 0 + u - 2 s ξ 0 cos γ 1 ξ 0 i = 1 , 3 , 4 . (B.7)

Antisymmetric modes:

u 1 a , u 3 a , u 4 a , v 1 a , v 3 a , v 4 a = u 1 a , u 3 a , u 4 a , v 1 a , v 3 a , v 4 a o f C a s e I u 2 a , u - 2 a , v 2 a , v - 2 a = u 2 s , - u - 2 s , - v 2 s , v - 2 s (B.8)

k 1 i = - u i a γ i sin γ i ξ 0 k 12 = - u 2 a γ 1 sin γ 1 ξ 0 + u - 2 a ( sin γ 1 ξ 0 + γ 1 ξ 0 cos γ 1 ξ 0 ) k 2 i = v i a sin γ i ξ 0 k 22 = v 2 a sin γ 1 ξ 0 + v - 2 a ξ 0 cos γ 1 ξ 0 k 3 i = sin γ i ξ 0 k 32 = ξ 0 cos γ 1 ξ 0 k 4 i = - D R γ i 2 sin γ i ξ 0 + A γ i cos γ i ξ 0 + B u i a cos γ i ξ 0 k 42 = - D R γ 1 2 sin γ 1 ξ 0 + γ 1 ξ 0 cos γ 1 ξ 0 + A cos γ 1 ξ 0 - γ 1 ξ 0 sin γ 1 ξ 0 + B u 2 a cos γ 1 ξ 0 + u - 2 a ξ 0 sin γ 1 ξ 0 i = 1 , 3 , 4 . (B.9)

B.3 Case III

Symmetric modes:

( u 3 s , u 4 s , v 3 s , v 4 s ) = ( u 3 s , u 4 s , v 3 s , v 4 s ) o f C a s e I u 1 s = ν - 1 4 β 1 u - 1 s = 1 + ν α 1 4 β 1 2 u 2 s , u - 2 s = u - 1 s , - u 1 s v 1 s = 1 2 k + 1 + ν k 4 β 1 2 v - 1 s = α 1 2 k β 1 v 2 s , v - 2 s = ( - v - 1 s , v 1 s ) (B.10)

k 1 i = α 1 u i s + β 1 u - i s cosh α 1 ξ 0 cos β 1 ξ 0 + α 1 u - i s - β 1 u i s sinh α 1 ξ 0 sin β 1 ξ 0 i = 1 , 2 k 1 i = u i s γ i cos γ i ξ 0 i = 3 , 4 k 2 i = v i s sinh α 1 ξ 0 sin β 1 ξ 0 + v - i s cosh α 1 ξ 0 cos β 1 ξ 0 i = 1 , 2 k 2 i = v i s cos γ i ξ 0 i = 3 , 4 k 31 = sinh α 1 ξ 0 sin β 1 ξ 0 k 32 = cosh α 1 ξ 0 cos β 1 ξ 0 k 3 i = cos γ i ξ 0 i = 3 , 4 k 41 = D R α 1 2 - β 1 2 sinh α 1 ξ 0 sin β 1 ξ 0 + 2 α 1 β 1 cosh α 1 ξ 0 cos β 1 ξ 0 + A α 1 + B u - 1 s cosh α 1 ξ 0 sin β 1 ξ 0 + A β 1 + B u 1 s sinh α 1 ξ 0 cos β 1 ξ 0 k 42 = D R α 1 2 - β 1 2 cosh α 1 ξ 0 cos β 1 ξ 0 - 2 α 1 β 1 sinh α 1 ξ 0 sin β 1 ξ 0 + A α 1 + B u 2 s sinh α 1 ξ 0 cos β 1 ξ 0 - A β 1 - B u - 2 s cosh α 1 ξ 0 sin β 1 ξ 0 k 4 i = - D R γ i 2 cos γ i ξ 0 - A γ i sin γ i ξ 0 + B u i s sin γ i ξ 0 i = 3 , 4 . (B.11)

Antisymmetric modes:

u 1 a , u - 1 a , u 2 a , u - 2 a , v 1 a , v - 1 a , v 2 a , v - 2 a = - u 1 s , u - 1 s , u - 1 s , u 1 s , v 1 s , - v - 1 s , v - 1 s , v 1 s u 3 a , u 4 a , v 3 a , v 4 a = u 3 a , u 4 a , v 3 a , v 4 a o f C a s e I (B.12)

k 1 i = α 1 u i a - β 1 u - i a cosh α 1 ξ 0 sin β 1 ξ 0 + α 1 u - i a + β 1 u i a sinh α 1 ξ 0 cos β 1 ξ 0 i = 1 , 2 k 1 i = - u i a γ i sin γ i ξ 0 i = 3 , 4 k 2 i = v i a sinh α 1 ξ 0 cos β 1 ξ 0 + v - i a cosh α 1 ξ 0 sin β 1 ξ 0 i = 1 , 2 k 2 i = v i a sin γ i ξ 0 i = 3 , 4 k 31 = sinh α 1 ξ 0 cos β 1 ξ 0 k 32 = cosh α 1 ξ 0 sin β 1 ξ 0 k 3 i = sin γ i ξ 0 i = 3 , 4 k 41 = D R α 1 2 - β 1 2 sinh α 1 ξ 0 cos β 1 ξ 0 - 2 α 1 β 1 cosh α 1 ξ 0 sin β 1 ξ 0 + A α 1 + B u - 1 a cosh α 1 ξ 0 cos β 1 ξ 0 - A β 1 - B u 1 a sinh α 1 ξ 0 sin β 1 ξ 0 k 42 = D R α 1 2 - β 1 2 cosh α 1 ξ 0 sin β 1 ξ 0 + 2 α 1 β 1 sinh α 1 ξ 0 cos β 1 ξ 0 + A α 1 + B u 2 a sinh α 1 ξ 0 sin β 1 ξ 0 + A β 1 + B u - 2 a cosh α 1 ξ 0 cos β 1 ξ 0 k 4 i = - D R γ i 2 sin γ i ξ 0 + A γ i cos γ i ξ 0 + B u i a cos γ i ξ 0 i = 3 , 4 . (B.13)

B.4 Case IV

Symmetric modes:

u 1 s , u - 1 s , u 2 s , u - 2 s , v 1 s , v - 1 s , v 2 s , v - 2 s = u 1 s , u - 1 s , u 2 s , u - 2 s , v 1 s , v - 1 s , v 2 s , v - 2 s o f C a s e I I I u 3 s , v 3 s = u 3 s , v 3 s o f C a s e I . B.14)

The coefficients (u4s, u-4s, v4s, v-4s) remain the same as those of (u2s, u-2s, v2s, v-2s) found in Case II with γ1 replaced by γ3.

k 1 i = α 1 u i s + β 1 u - i s cosh α 1 ξ 0 cos β 1 ξ 0 + α 1 u - i s - β 1 u i s sinh α 1 ξ 0 sin β 1 ξ 0 i = 1 , 2 k 13 = u 3 s γ 3 cos γ 3 ξ 0 k 14 = u 4 s γ 3 cos γ 3 ξ 0 + u - 4 s ( cos γ 3 ξ 0 - γ 3 ξ 0 sin γ 3 ξ 0 ) k 2 i = v i s sinh α 1 ξ 0 sin β 1 ξ 0 + v - i s cosh α 1 ξ 0 cos β 1 ξ 0 i = 1 , 2 k 23 = v 3 s cos γ 3 ξ 0 k 24 = v 4 s cos γ 3 ξ 0 + v - 4 s ξ 0 sin γ 3 ξ 0 k 31 = sinh α 1 ξ 0 sin β 1 ξ 0 k 32 = cosh α 1 ξ 0 cos β 1 ξ 0 k 33 = cos γ 3 ξ 0 k 34 = ξ 0 sin γ 3 ξ 0 k 41 = D R α 1 2 - β 1 2 sinh α 1 ξ 0 sin β 1 ξ 0 + 2 α 1 β 1 cosh α 1 ξ 0 cos β 1 ξ 0 + A α 1 + B u - 1 s cosh α 1 ξ 0 sin β 1 ξ 0 + A β 1 + B u 1 s sinh α 1 ξ 0 cos β 1 ξ 0 k 42 = D R α 1 2 - β 1 2 cosh α 1 ξ 0 cos β 1 ξ 0 - 2 α 1 β 1 sinh α 1 ξ 0 sin β 1 ξ 0 + A α 1 + B u 2 s sinh α 1 ξ 0 cos β 1 ξ 0 - A β 1 - B u - 2 s cosh α 1 ξ 0 sin β 1 ξ 0 k 43 = - D R γ 3 2 cos γ 3 ξ 0 - A γ 3 sin γ 3 ξ 0 + B u 3 s sin γ 3 ξ 0 k 44 = D R γ 3 2 cos γ 3 ξ 0 - γ 3 ξ 0 sin γ 3 ξ 0 + A sin γ 3 ξ 0 + γ 3 ξ 0 cos γ 3 ξ 0 + B u 4 s sin γ 3 ξ 0 + u - 4 s ξ 0 cos γ 3 ξ 0 . (B.15)

Antisymmetric modes:

u 1 a , u - 1 a , u 2 a , u - 2 a , v 1 a , v - 1 a , v 2 a , v - 2 a = u 1 a , u - 1 a , u 2 a , u - 2 a , v 1 a , v - 1 a , v 2 a , v - 2 a o f C a s e I I I u 3 a , v 3 a = u 3 a , v 3 a o f C a s e I . (B.16)

The coefficients (u4a, u-4a, v4a, v-4a) remain the same as those of (u2a, u-2a, v2a, v-2a) found in Case II with γ1 replaced by γ3.

k 1 i = α 1 u i a - β 1 u - i a cosh α 1 ξ 0 sin β 1 ξ 0 + α 1 u - i a + β 1 u i a sinh α 1 ξ 0 cos β 1 ξ 0 i = 1 , 2 k 13 = - u 3 a γ 3 sin γ 3 ξ 0 k 14 = - u 4 a γ 3 sin γ 3 ξ 0 + u - 4 a ( sin γ 3 ξ 0 + γ 3 ξ 0 cos γ 3 ξ 0 ) k 2 i = v i a sinh α 1 ξ 0 cos β 1 ξ 0 + v - i a cosh α 1 ξ 0 sin β 1 ξ 0 i = 1 , 2 k 23 = v 3 a sin γ 3 ξ 0 k 24 = v 4 a sin γ 3 ξ 0 + v - 4 a ξ 0 cos γ 3 ξ 0 k 31 = sinh α 1 ξ 0 cos β 1 ξ 0 k 32 = cosh α 1 ξ 0 sin β 1 ξ 0 k 33 = sin γ 3 ξ 0 k 34 = ξ 0 cos γ 3 ξ 0 k 41 = D R α 1 2 - β 1 2 sinh α 1 ξ 0 cos β 1 ξ 0 - 2 α 1 β 1 cosh α 1 ξ 0 sin β 1 ξ 0 + A α 1 + B u - 1 a cosh α 1 ξ 0 cos β 1 ξ 0 - A β 1 - B u 1 a sinh α 1 ξ 0 sin β 1 ξ 0 k 42 = D R α 1 2 - β 1 2 cosh α 1 ξ 0 sin β 1 ξ 0 + 2 α 1 β 1 sinh α 1 ξ 0 cos β 1 ξ 0 + A α 1 + B u 2 a sinh α 1 ξ 0 sin β 1 ξ 0 + A β 1 + B u - 2 a cosh α 1 ξ 0 cos β 1 ξ 0 k 43 = - D R γ 3 2 sin γ 3 ξ 0 + A γ 3 cos γ 3 ξ 0 + B u 3 a cos γ 3 ξ 0 k 44 = - D R γ 3 2 sin γ 3 ξ 0 + γ 3 ξ 0 cos γ 3 ξ 0 + A cos γ 3 ξ 0 - γ 3 ξ 0 sin γ 3 ξ 0 + B u 4 a cos γ 3 ξ 0 + u - 4 a ξ 0 sin γ 3 ξ 0 . (B.17)

B.5 Case V

Symmetric modes:

u 1 s , u - 1 s , u 2 s , u - 2 s , v 1 s , v - 1 s , v 2 s , v - 2 s = u 1 s , u - 1 s , u 2 s , u - 2 s , v 1 s , v - 1 s , v 2 s , v - 2 s o f C a s e I I I . (B.18)

The coefficients (u3s, u-3s, v3s, v-3s) and (v-3s, v-3s, v4s, v-4s) remain the same as those of (u1s, u-1s, v1s, v-1s) and (u2s, u-2s, v2s, v-2s), respectively, with α1 and β1 replaced by α2 and β2.

k 1 i = α 1 u i s + β 1 u - i s cosh α 1 ξ 0 cos β 1 ξ 0 + α 1 u - i s - β 1 u i s sinh α 1 ξ 0 sin β 1 ξ 0 i = 1 , 2 k 1 i = α 2 u i s + β 2 u - i s cosh α 2 ξ 0 cos β 2 ξ 0 + α 2 u - i s - β 2 u i s sinh α 2 ξ 0 sin β 2 ξ 0 i = 3 , 4 k 2 i = v i s sinh α 1 ξ 0 sin β 1 ξ 0 + v - i s cosh α 1 ξ 0 cos β 1 ξ 0 i = 1 , 2 k 2 i = v i s sinh α 2 ξ 0 sin β 2 ξ 0 + v - i s cosh α 2 ξ 0 cos β 2 ξ 0 i = 3 , 4 k 31 = sinh α 1 ξ 0 sin β 1 ξ 0 k 32 = cosh α 1 ξ 0 cos β 1 ξ 0 k 33 = sinh α 2 ξ 0 sin β 2 ξ 0 k 34 = cosh α 2 ξ 0 cos β 2 ξ 0 k 41 = D R α 1 2 - β 1 2 sinh α 1 ξ 0 sin β 1 ξ 0 + 2 α 1 β 1 cosh α 1 ξ 0 cos β 1 ξ 0 + A α 1 + B u - 1 s cosh α 1 ξ 0 sin β 1 ξ 0 + A β 1 + B u 1 s sinh α 1 ξ 0 cos β 1 ξ 0 k 42 = D R α 1 2 - β 1 2 cosh α 1 ξ 0 cos β 1 ξ 0 - 2 α 1 β 1 sinh α 1 ξ 0 sin β 1 ξ 0 + A α 1 + B u 2 s sinh α 1 ξ 0 cos β 1 ξ 0 - A β 1 - B u - 2 s cosh α 1 ξ 0 sin β 1 ξ 0 k 43 = D R α 2 2 - β 2 2 sinh α 2 ξ 0 sin β 2 ξ 0 + 2 α 2 β 2 cosh α 2 ξ 0 cos β 2 ξ 0 + A α 2 + B u - 3 s cosh α 2 ξ 0 sin β 2 ξ 0 + A β 2 + B u 3 s sinh α 2 ξ 0 cos β 2 ξ 0 k 44 = D R α 2 2 - β 2 2 cosh α 2 ξ 0 cos β 2 ξ 0 - 2 α 2 β 2 sinh α 2 ξ 0 sin β 2 ξ 0 + A α 2 + B u 4 s sinh α 2 ξ 0 cos β 2 ξ 0 - A β 2 - B u - 4 s cosh α 2 ξ 0 sin β 2 ξ 0 . (B.19)

Antisymmetric modes:

u 1 a , u - 1 a , u 2 a , u - 2 a , v 1 a , v - 1 a , v 2 a , v - 2 a = - u 1 s , u - 1 s , u - 1 s , u 1 s , v 1 s , - v - 1 s , v - 1 s , v 1 s (B.20)

The coefficients (u3a, u-3a, v3a, v-3a) and (u4a, u-4a, v4a, v-4a) remain the same as those of (u1a, u1a, v1a, v-1a) and (u2a, u-2a, v2a, v-2a), respectively, with α1 and β1 replaced by α2 and β2.

k 1 i = α 1 u i a - β 1 u - i a cosh α 1 ξ 0 sin β 1 ξ 0 + α 1 u - i a + β 1 u i a sinh α 1 ξ 0 cos β 1 ξ 0 i = 1 , 2 k 1 i = α 2 u i a - β 2 u - i a cosh α 2 ξ 0 sin β 2 ξ 0 + α 2 u - i a + β 2 u i a sinh α 2 ξ 0 cos β 2 ξ 0 i = 3 , 4 k 1 i = α 2 u i a - β 2 u - i a cosh α 2 ξ 0 sin β 2 ξ 0 + α 2 u - i a + β 2 u i a sinh α 2 ξ 0 cos β 2 ξ 0 i = 3 , 4 k 2 i = v i a sinh α 2 ξ 0 cos β 2 ξ 0 + v - i a cosh α 2 ξ 0 sin β 2 ξ 0 i = 3 , 4 k 31 = sinh α 1 ξ 0 cos β 1 ξ 0 k 32 = cosh α 1 ξ 0 sin β 1 ξ 0 k 33 = sinh α 2 ξ 0 cos β 2 ξ 0 k 34 = cosh α 2 ξ 0 sin β 2 ξ 0 k 41 = D R α 1 2 - β 1 2 sinh α 1 ξ 0 cos β 1 ξ 0 - 2 α 1 β 1 cosh α 1 ξ 0 sin β 1 ξ 0 + A α 1 + B u - 1 a cosh α 1 ξ 0 cos β 1 ξ 0 - A β 1 - B u 1 a sinh α 1 ξ 0 sin β 1 ξ 0 k 42 = D R α 1 2 - β 1 2 cosh α 1 ξ 0 sin β 1 ξ 0 + 2 α 1 β 1 sinh α 1 ξ 0 cos β 1 ξ 0 + A α 1 + B u 2 a sinh α 1 ξ 0 sin β 1 ξ 0 + A β 1 + B u - 2 a cosh α 1 ξ 0 cos β 1 ξ 0 k 43 = D R α 2 2 - β 2 2 sinh α 2 ξ 0 cos β 2 ξ 0 - 2 α 2 β 2 cosh α 2 ξ 0 sin β 2 ξ 0 + A α 2 + B u - 3 a cosh α 2 ξ 0 cos β 2 ξ 0 - A β 2 - B u 3 a sinh α 2 ξ 0 sin β 2 ξ 0 k 44 = D R α 2 2 - β 2 2 cosh α 2 ξ 0 sin β 2 ξ 0 + 2 α 2 β 2 sinh α 2 ξ 0 cos β 2 ξ 0 + ( A α 2 + B u 4 a ) sinh α 2 ξ 0 sin β 2 ξ 0 + ( A β 2 + B u ¯ 4 a ) cosh α 2 ξ 0 cos β 2 ξ 0 . (B.21)

Edited by

Guest Editors:

Volnei Tita and Nicholas Fantuzzi.

Publication Dates

  • Publication in this collection
    09 Nov 2020
  • Date of issue
    2020

History

  • Received
    16 Dec 2019
  • Reviewed
    01 Aug 2020
  • Accepted
    28 Aug 2020
  • Published
    01 Sept 2020
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